Algebra Precalculus Multiple Choice Sum Of Primes Below 1000

My attempt to solve it We know that below 1000 there are 167 odd primes and 1 even prime (2), so the sum has to be odd, leaving only the first two numbers.

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Furthermore, creating arithmetic expression equal to 1000 using exactly eight 8's I would like to find all the expressions that can be created using nothing but arithmetic operators, exactly eight 8's, and parentheses. Here are the seven solutions I've found (on the Internet). This aspect of Algebra Precalculus Multiple Choice Sum Of Primes Below 1000 plays a vital role in practical applications.

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